Nibble

Archive for September, 2008

Converting Linebreaks 3

Posted September 28, 2008

When using the textbox multiple datatype in umbraco you might want to convert the linebreaks into html <br> tags. This can be done just by checking a checkbox in the insert umbraco field dialog when inserting a field on your template. Just look for the convert linebreaks checkbox.

image

 

image 

 

In xslt you can also do this by using the umbraco library method umbraco.library.ReplaceLineBreaks(System.String)

So that would like a this:

<xsl:value-of select=”umbraco.library:ReplaceLineBreaks(data [@alias = ‘youralias’])”/>

XSLT previous,next example 5

Posted September 4, 2008

Say you have a structure like this on your site.

xslt

Multiple content items of the same documenttype, like news items. And you want to display a previous and a next link on those news items.

This can be done with some xslt. Here is an example:

<?xml version=”1.0″ encoding=”UTF-8″?>
<!DOCTYPE xsl:stylesheet [ &lt;!ENTITY nbsp “&#x00A0;”> ]>
<xsl:stylesheet 
    version=”1.0″ 
    xmlns:xsl=”http://www.w3.org/1999/XSL/Transform” 
    xmlns:msxml=”urn:schemas-microsoft-com:xslt”
    xmlns:umbraco.library=”urn:umbraco.library”
    exclude-result-prefixes=”msxml umbraco.library”>
 
<xsl:output method=”xml” omit-xml-declaration=”yes” />
 
<xsl:param name=”currentPage”/>
 
<xsl:template match=”/”>
 
<!– The fun starts here –>
 
<xsl:for-each select=”$currentPage/ancestor-or-self::node [@nodeTypeAlias = ‘NewsPage’]/node”>
 
<xsl:if test=”$currentPage/@id = current()/@id”>
 
 <xsl:call-template name=”prevnext”>
    <xsl:with-param name=”count” select=”count($currentPage/ancestor-or-self::node [@nodeTypeAlias = ‘NewsPage’]/node)”/>
    <xsl:with-param name=”itemindex” select=”position()”/>
  </xsl:call-template>
</xsl:if>
 
</xsl:for-each>
 
</xsl:template>
 
<xsl:template name=”prevnext” >
<xsl:param name=”count” />
<xsl:param name=”itemindex” />
 
<xsl:if test=”$itemindex > 1″>
<a href=”{umbraco.library:NiceUrl($currentPage/ancestor-or-self::node [@nodeTypeAlias = ‘NewsPage’]/node[$itemindex-1]/@id)}”>
Previous</a>
</xsl:if>
 
<xsl:if test=”$itemindex &lt; $count”>
<a href=”{umbraco.library:NiceUrl($currentPage/ancestor-or-self::node [@nodeTypeAlias = ‘NewsPage’]/node[$itemindex +1]/@id)}”>
Next </a>
</xsl:if>
 
</xsl:template>
 
</xsl:stylesheet>

The Key is to know how many nodes(newsitems) there are and what the position of the current node is (first, second, .. last) because you don’t need to display a previous link if it’s the first item or a next link if it’s the last.

UPDATE:

Petr Snobelt mailed me the following snippet, which shows another technique (no for-each loop, so should be faster)

<xsl:if test=”count($currentPage/preceding-sibling::node) != 0″>
previous
<a href=”{umbraco.library:NiceUrl($currentPage/preceding-sibling::node[1]/@id)}”>
 <xsl:value-of select=”$currentPage/preceding-sibling::node[1]/@nodeName”/>
</a>
<br />
</xsl:if>
 
<xsl:if test=”count($currentPage/following-sibling::node) != 0″>
next
<a href=”{umbraco.library:NiceUrl($currentPage/following-sibling::node[1]/@id)}”>
 <xsl:value-of select=”$currentPage/following-sibling::node[1]/@nodeName”/>
</a>
</xsl:if>